Exercice 37: write the solution which puts declarations and definitions together.

TP/4-Templates/Solution/exercice37.cpp

@@ -174,20 +174,41 @@ private:
 };
 
 
-//! Returns `number` * (2 ^ `exponent`) 
-int times_power_of_2(int number, int exponent);
+int times_power_of_2(int number, int exponent)
+{
+    while (exponent > 0)
+    { 
+        number *= 2; 
+        exponent -= 1; 
+    }
+    while (exponent < 0)
+    { 
+        number /= 2;
+        exponent += 1 ; 
+    }
+    
+    return number;
+}
+
 
+int round_as_int(double x)
+{
+    return static_cast<int>(std::round(x));
+}
 
-//! Round to `x` the nearest integer.
-int round_as_int(double x);
 
+int max_int(int Nbits)
+{ 
+    return (times_power_of_2(1, Nbits) - 1);
+}
 
-//! Maximum integer that might be represented with `Nbits` bits.
-int max_int(int Nbits);
 
+[[noreturn]] void error(std::string explanation)
+{
+    std::cout << "ERROR: " << explanation << std::endl;
+    exit(EXIT_FAILURE);
+}
 
-//! Function to call when an error occurred; its aborts the program.
-[[noreturn]] void error(std::string explanation);
 
 
 //! Class which stores several `TestDisplay` as pointers.
@@ -252,41 +273,6 @@ int main(int argc, char** argv)
 /************************************/
 
 
-int times_power_of_2(int number, int exponent)
-{
-    while (exponent > 0)
-    { 
-        number *= 2; 
-        exponent -= 1; 
-    }
-    while (exponent < 0)
-    { 
-        number /= 2;
-        exponent += 1 ; 
-    }
-    
-    return number;
-}
-
-
-int round_as_int(double x)
-{
-    return static_cast<int>(std::round(x));
-}
-
-
-int max_int(int Nbits)
-{ 
-    return (times_power_of_2(1, Nbits) - 1);
-}
-
-
-[[noreturn]] void error(std::string explanation)
-{
-    std::cout << "ERROR: " << explanation << std::endl;
-    exit(EXIT_FAILURE);
-}
-
 
 /*==================================*/
 // PowerOfTwoApprox