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Pierre-Marie Pédrot authored
When this option is passed the integer 0, it now replaces the par: selector with an equivalent combinator that does not spawn any new process and behaves as all: solve [tac] instead. This is different from when passed the integer 1, which means that a process is still spawned although it doesn't parallelize anything.
Pierre-Marie Pédrot authoredWhen this option is passed the integer 0, it now replaces the par: selector with an equivalent combinator that does not spawn any new process and behaves as all: solve [tac] instead. This is different from when passed the integer 1, which means that a process is still spawned although it doesn't parallelize anything.