Make the Faust-by-vector multiplication return a 1D vector as numpy does...

Make the Faust-by-vector multiplication return a 1D vector as numpy does (instead of a matrix with a dimension size at 1).

Undo the conversion of the result into a numpy.matrix added by commit 421e8251 because it makes impossible to squeeze the 2nd dimension of the vector (a numpy.matrix has necessarily two dimensions).

This commit fixes the error demonstrated in issue #56 (with pyunlocbox).

wrapper/python/src/FaustCorePy.pyx

@@ -393,14 +393,15 @@ cdef class FaustCore:
             else:
                 self.core_faust_cplx.multiply(&yview_cplx[0,0], nbrow_y,
                                               nbcol_y, &xview_1D_cplx[0], nbrow_x,nbcol_x)
+            y = np.squeeze(y) # we want a single dim. (but we created two
+            # above)
         else:
             if(self._isReal):
                 self.core_faust_dbl.multiply(&yview[0,0],nbrow_y,nbcol_y,&xview_2D[0,0],nbrow_x,nbcol_x)
             else:
                 self.core_faust_cplx.multiply(&yview_cplx[0,0],nbrow_y,nbcol_y,&xview_2D_cplx[0,0],nbrow_x,nbcol_x)
 
-        return np.matrix(y, copy=False)
-
+        return y
 
 
     # print information about the faust (size, number of factor, type of factor (dense/sparse) ...)