Documentation nle solver
Attention, ceci n'est plus vrai
>>> from nutopy import nle
>>> nle.solve(f, x0=1.0, df=f)
>>> # or equivalently: df is not required if f is tensorized
>>> nle.solve(f, x0=1.0)
cf.
#
if f is df:
jac_case = 2 # f is tensorized
elif df is None:
#if istensorized(f, (1,), x0, *args, **kwargs):
# df = f
# jac_case = 2 # f is tensorized
#else:
jac_case = 0 # no jacobian => finite diff
else:
jac_case = 1 # the Jacobian is given