native functions do not write back result in output from temporary variables

Created by: mbonani

when using a single element of a buffer in a call function the result is not correctly address in memory and is is lost in a temp example code buffer2 should have be filled with 50 after executing and here it is not:

var i
var buffer[5]
var buffer2[5]

call math.fill(buffer,10)
call math.fill(buffer2,0)

for  i in 0:4 do
    call math.muldiv(buffer2[i],buffer[i],10,2)
end

it work using an single temp

var i
var buffer[5]
var buffer2[5]
var t

call math.fill(buffer,10)
call math.fill(buffer2,0)

for  i in 0:4 do
    call math.muldiv(t,buffer[i],10,2)
    buffer2[i]=t
end