(* The purpose of this algorithm is to find, for each pair of a state [s] and a terminal symbol [z] such that looking at [z] in state [s] causes an error, a minimal path (starting in some initial state) that actually triggers this error. *) (* This is potentially useful for grammar designers who wish to better understand the properties of their grammar, or who wish to produce a list of all possible syntax errors (or, at least, one syntax error in each automaton state where an error may occur). *) (* The problem seems rather tricky. One might think that it suffices to compute shortest paths in the automaton, and to use [Analysis.minimal] to replace each non-terminal symbol in a path with a minimal word that this symbol generates. One can indeed do so, but this yields only a lower bound on the actual shortest path to the error at [s, z]. Indeed, two difficulties arise: - Some states have a default reduction. Thus, they will not trigger an error, even though they should. The error is triggered in some other state, after reduction takes place. - If the grammar has conflicts, conflict resolution removes some (shift or reduce) actions, hence may suppress the shortest path. *) (* We explicitly choose to ignore the [error] token. Thus, we disregard any reductions or transitions that take place when the lookahead symbol is [error]. As a result, any state whose incoming symbol is [error] is found unreachable. It would be too complicated to have to create a first error in order to be able to take certain transitions or drop certain parts of the input. *) (* We never work with the terminal symbol [#] either. This symbol never appears in the maps returned by [Lr1.transitions] and [Lr1.reductions]. Thus, in principle, we work with ``real'' terminal symbols only. However, we encode [any] as [#] -- see below. *) (* NOTE: THIS FILE IS COMPILED WITH -noassert BY DEFAULT. If you would like the assertions to be tested at runtime, change that in the file _tags. *) (* ------------------------------------------------------------------------ *) (* To delay the side effects performed by this module, we wrap everything in in a big functor without arguments. *) module Run (X : sig val verbose: bool end) = struct open Grammar (* ------------------------------------------------------------------------ *) (* Because of our encoding of terminal symbols as 8-bit characters, this algorithm supports at most 256 terminal symbols. *) let () = if Terminal.n > 256 then Error.error [] (Printf.sprintf "--list-errors supports at most 256 terminal symbols.\n\ The grammar has %d terminal symbols." Terminal.n ) (* ------------------------------------------------------------------------ *) (* Build a module that represents words as (hash-consed) strings. Note: this functor application has a side effect (it allocates memory, and more importantly, it may fail). *) module W = Terminal.Word(struct end) (* ------------------------------------------------------------------------ *) (* The [error] token may appear in the maps returned by [Lr1.transitions] and [Lr1.reductions], so we sometimes need to explicitly check for it. *) let non_error z = not (Terminal.equal z Terminal.error) (* We introduce a pseudo-terminal symbol [any]. It is used in several places later on, in particular in the field [fact.lookahead], to encode the absence of a lookahead hypothesis -- i.e., any terminal symbol will do. *) (* We choose to encode [any] as [#]. There is no risk of confusion, since we do not use [#] anywhere. Thus, the assertion [Terminal.real z] implies [z <> any]. *) let any = Terminal.sharp (* ------------------------------------------------------------------------ *) (* We begin with a number of auxiliary functions that provide information about the LR(1) automaton. These functions could perhaps be moved to a separate module. We keep them here, for the moment, because they are not used anywhere else. *) (* [reductions_on s z] is the list of reductions permitted in state [s] when the lookahead symbol is [z]. This is a list of zero or one elements. This does not take default reductions into account. *) let reductions_on s z : Production.index list = assert (Terminal.real z); try TerminalMap.find z (Lr1.reductions s) with Not_found -> [] (* [has_reduction s z] tells whether state [s] is willing to reduce some production (and if so, which one) when the lookahead symbol is [z]. It takes a possible default reduction into account. *) let has_reduction s z : Production.index option = assert (Terminal.real z); match Invariant.has_default_reduction s with | Some (prod, _) -> Some prod | None -> match reductions_on s z with | prod :: prods -> assert (prods = []); Some prod | [] -> None (* [can_reduce s prod] indicates whether state [s] is able to reduce production [prod] (either as a default reduction, or as a normal reduction). *) let can_reduce s prod = match Invariant.has_default_reduction s with | Some (prod', _) when prod = prod' -> true | _ -> TerminalMap.fold (fun z prods accu -> (* A reduction on [#] is always a default reduction. (See [lr1.ml].) *) assert (not (Terminal.equal z Terminal.sharp)); accu || non_error z && List.mem prod prods ) (Lr1.reductions s) false (* [causes_an_error s z] tells whether state [s] will initiate an error on the lookahead symbol [z]. *) let causes_an_error s z : bool = assert (Terminal.real z); match Invariant.has_default_reduction s with | Some _ -> false | None -> reductions_on s z = [] && not (SymbolMap.mem (Symbol.T z) (Lr1.transitions s)) (* [foreach_terminal f] applies the function [f] to every terminal symbol in turn, except [error] and [#]. *) let foreach_terminal = Terminal.iter_real (* [foreach_terminal_not_causing_an_error s f] applies the function [f] to every terminal symbol [z] such that [causes_an_error s z] is false. This could be implemented in a naive manner using [foreach_terminal] and [causes_an_error]. This implementation is significantly more efficient. *) let foreach_terminal_not_causing_an_error s f = match Invariant.has_default_reduction s with | Some _ -> (* There is a default reduction. No symbol causes an error. *) foreach_terminal f | None -> (* Enumerate every terminal symbol [z] for which there is a reduction. *) TerminalMap.iter (fun z _ -> (* A reduction on [#] is always a default reduction. (See [lr1.ml].) *) assert (not (Terminal.equal z Terminal.sharp)); if non_error z then f z ) (Lr1.reductions s); (* Enumerate every terminal symbol [z] for which there is a transition. *) SymbolMap.iter (fun sym _ -> match sym with | Symbol.T z -> assert (not (Terminal.equal z Terminal.sharp)); if non_error z then f z | Symbol.N _ -> () ) (Lr1.transitions s) (* Let us say a state [s] is solid if its incoming symbol is a terminal symbol (or if it has no incoming symbol at all, i.e., it is an initial state). It is fragile if its incoming symbol is a non-terminal symbol. *) let is_solid s = match Lr1.incoming_symbol s with | None | Some (Symbol.T _) -> true | Some (Symbol.N _) -> false (* ------------------------------------------------------------------------ *) (* Suppose [s] is a state that carries an outgoing edge labeled with a non-terminal symbol [nt]. We are interested in finding out how this edge can be taken. In order to do that, we must determine how, by starting in [s], one can follow a path that corresponds to (the right-hand side of) a production [prod] associated with [nt]. There are in general several such productions. The paths that they determine in the automaton form a "star". We represent the star rooted at [s] as a trie. For every state [s], the star rooted at [s] is constructed in advance, before the algorithm runs. While the algorithm runs, a point in the trie (that is, a sub-trie) tells us where we come from, where we are, and which production(s) we are hoping to reduce in the future. *) module Trie : sig type trie (* [star s] creates a (new) trie whose source is [s], populated with its branches. (There is one branch for every production [prod] associated with every non-terminal symbol [nt] for which [s] carries an outgoing edge.) If the star turns out to be trivial then [None] is returned. *) val star: Lr1.node -> trie option (* After [star s] has been called, [size (Lr1.number s)] reports the size of the trie that has been constructed for state [s]. *) val size: int -> int (* Every (sub-)trie has a unique identity. (One can think of it as its address.) [compare] compares the identity of two tries. This can be used, e.g., to set up a map whose keys are tries. *) val compare: trie -> trie -> int (* [source t] returns the source state of the (sub-)trie [t]. This is the root of the star of which [t] is a sub-trie. In other words, this tells us "where we come from". *) val source: trie -> Lr1.node (* [current t] returns the current state of the (sub-)trie [t]. This is the root of the sub-trie [t]. In other words, this tells us "where we are". *) val current: trie -> Lr1.node (* [accepts prod t] tells whether the current state of the trie [t] is the end of a branch associated with production [prod]. If so, this means that we have successfully followed a path that corresponds to the right-hand side of production [prod]. *) val accepts: Production.index -> trie -> bool (* [step sym t] is the immediate sub-trie of [t] along the symbol [sym]. This function raises [Not_found] if [t] has no child labeled [sym]. *) val step: Symbol.t -> trie -> trie (* [verbose()] outputs debugging & performance information. *) val verbose: unit -> unit end = struct (* A trie has the following structure. *) type trie = { (* A unique identity, used by [compare]. The trie construction code ensures that these numbers are indeed unique: see [fresh], [insert], [star]. *) identity: int; (* The root state of this star: "where we come from". *) source: Lr1.node; (* The current state, i.e., the root of this sub-trie: "where we are". *) current: Lr1.node; (* The productions that we can reduce in the current state. In other words, if this list is nonempty, then the current state is the end of one (or several) branches. It can nonetheless have children. *) productions: Production.index list; (* The children, or sub-tries. *) transitions: trie SymbolMap.t } (* This counter is used by [mktrie] to produce unique identities. *) let c = ref 0 (* This smart constructor creates a new trie with a unique identity. *) let mktrie source current productions transitions = let identity = Misc.postincrement c in { identity; source; current; productions; transitions } exception DeadBranch let rec insert w prod t = match w with | [] -> (* We check whether the current state [t.current] is able to reduce production [prod]. (If [prod] cannot be reduced, the reduction action must have been suppressed by conflict resolution.) If not, then this branch is dead. This test is superfluous (i.e., it would be OK to conservatively assume that [prod] can be reduced) but allows us to build a slightly smaller star in some cases. *) if can_reduce t.current prod then (* We consume (update) the trie [t], so there is no need to allocate a new stamp. (Of course we could allocate a new stamp, but I prefer to be precise.) *) { t with productions = prod :: t.productions } else raise DeadBranch | (Symbol.T t) :: _ when Terminal.equal t Terminal.error -> raise DeadBranch | a :: w -> (* Check if there is a transition labeled [a] out of [t.current]. If there is, we add a child to the trie [t]. If there isn't, then it must have been removed by conflict resolution. (Indeed, it must be present in a canonical automaton.) We could in this case return an unchanged sub-trie. We can do slightly better: we abort the whole insertion, so as to return an unchanged toplevel trie. *) match SymbolMap.find a (Lr1.transitions t.current) with | successor -> (* Find our child at [a], or create it. *) let t' = try SymbolMap.find a t.transitions with Not_found -> mktrie t.source successor [] SymbolMap.empty in (* Update the child [t']. *) let t' = insert w prod t' in (* Update [t]. Again, no need to allocate a new stamp. *) { t with transitions = SymbolMap.add a t' t.transitions } | exception Not_found -> raise DeadBranch (* [insert prod t] inserts a new branch, corresponding to production [prod], into the trie [t]. This function consumes its argument, which should no longer be used afterwards. *) let insert prod t = let w = Array.to_list (Production.rhs prod) in let save = !c in try insert w prod t with DeadBranch -> c := save; t (* [fresh s] creates a new empty trie whose source is [s]. *) let fresh source = mktrie source source [] SymbolMap.empty (* The star at [s] is obtained by starting with a fresh empty trie and inserting into it every production [prod] whose left-hand side [nt] is the label of an outgoing edge at [s]. *) let star s = SymbolMap.fold (fun sym _ accu -> match sym with | Symbol.T _ -> accu | Symbol.N nt -> Production.foldnt nt accu insert ) (Lr1.transitions s) (fresh s) (* A trie [t] is nontrivial if it has at least one branch, i.e., contains at least one sub-trie whose [productions] field is nonempty. Trivia: a trie of size greater than 1 is necessarily nontrivial, but the converse is not true: a nontrivial trie can have size 1. (This occurs if all productions have zero length.) *) let trivial t = t.productions = [] && SymbolMap.is_empty t.transitions (* Redefine [star] to include a [nontrivial] test and to record the size of the newly built trie. *) let size = Array.make Lr1.n (-1) let star s = let initial = !c in let t = star s in let final = !c in size.(Lr1.number s) <- final - initial; if trivial t then None else Some t let size s = assert (size.(s) >= 0); size.(s) let compare t1 t2 = Pervasives.compare t1.identity t2.identity let source t = t.source let current t = t.current let accepts prod t = List.mem prod t.productions let step a t = SymbolMap.find a t.transitions (* careful: may raise [Not_found] *) let verbose () = Printf.eprintf "Cumulated star size: %d\n%!" !c end (* ------------------------------------------------------------------------ *) (* The main algorithm, [LRijkstra], accumulates facts. A fact is a triple of a position (that is, a sub-trie), a word, and a lookahead assumption. Such a fact means that this position can be reached, from the source state [Trie.source fact.position], by consuming [fact.word], under the assumption that the next input symbol is [fact.lookahead]. *) (* We allow [fact.lookahead] to be [any] so as to indicate that this fact does not have a lookahead assumption. *) type fact = { position: Trie.trie; word: W.word; lookahead: Terminal.t (* may be [any] *) } (* Accessors. *) let source fact = Trie.source fact.position let current fact = Trie.current fact.position (* Two invariants reduce the number of facts that we consider: 1. If [fact.lookahead] is a real terminal symbol [z] (i.e., not [any]), then [z] does not cause an error in the current state [current fact]. It would be useless to consider a fact that violates this property; this cannot possibly lead to a successful reduction. In practice, this refinement allows reducing the number of facts that go through the queue by a factor of two. 2. [fact.lookahead] is [any] iff the current state [current fact] is solid. This sounds rather reasonable (when a state is entered by shifting, it is entered regardless of which symbol follows) and simplifies the implementation of the sub-module [T]. *) let invariant1 fact = fact.lookahead = any || not (causes_an_error (current fact) fact.lookahead) let invariant2 fact = (fact.lookahead = any) = is_solid (current fact) (* [compatible z a] checks whether the terminal symbol [a] satisfies the lookahead assumption [z] -- which can be [any]. *) let compatible z a = assert (non_error z); assert (Terminal.real a); z = any || z = a (* ------------------------------------------------------------------------ *) (* As in Dijkstra's algorithm, a priority queue contains the facts that await examination. The length of [fact.word] serves as the priority of a fact. This guarantees that we discover shortest paths. (We never insert into the queue a fact whose priority is less than the priority of the last fact extracted out of the queue.) *) (* [LowIntegerPriorityQueue] offers very efficient operations (essentially constant time, for a small constant). It exploits the fact that priorities are low nonnegative integers. *) module Q = LowIntegerPriorityQueue let q = Q.create() (* In principle, there is no need to insert the fact into the queue if [T] already stores a comparable fact. We could perform this test in [add]. However, a quick experiment suggests that this is not worthwhile. The run time augments (because membership in [T] is tested twice, upon inserting and upon extracting) and the memory consumption does not seem to go down significantly. *) let add fact = (* [fact.lookahead] can be [any], but cannot be [error] *) assert (non_error fact.lookahead); assert (invariant1 fact); assert (invariant2 fact); (* The length of [fact.word] serves as the priority of this fact. *) Q.add q fact (W.length fact.word) (* ------------------------------------------------------------------------ *) (* Construct the [star] of every state [s]. Initialize the priority queue. *) let () = (* For every state [s]... *) Lr1.iter (fun s -> (* If the trie rooted at [s] is nontrivial...*) match Trie.star s with | None -> () | Some position -> (* ...then insert an initial fact into the priority queue. *) (* In order to respect invariants 1 and 2, we must distinguish two cases. If [s] is solid, then we insert a single fact, whose lookahead assumption is [any]. Otherwise, we must insert one initial fact for every terminal symbol [z] that does not cause an error in state [s]. *) let word = W.epsilon in if is_solid s then add { position; word; lookahead = any } else foreach_terminal_not_causing_an_error s (fun z -> add { position; word; lookahead = z } ) ); if X.verbose then Trie.verbose() (* ------------------------------------------------------------------------ *) (* The module [T] maintains a set of known facts. *) (* Three aspects of a fact are of particular interest: - its position [position], given by [fact.position]; - its first symbol [a], given by [W.first fact.word fact.lookahead]; - its lookahead assumption [z], given by [fact.lookahead]. For every triple of [position], [a], and [z], we store at most one fact, (whose word has minimal length). Indeed, we are not interested in keeping track of several words that produce the same effect. Only the shortest such word is of interest. Thus, the total number of facts accumulated by the algorithm is at most [T.n^2], where [T] is the total size of the tries that we have constructed, and [n] is the number of terminal symbols. (This number can be quite large. [T] can be in the tens of thousands, and [n] can be over one hundred. These figures lead to a theoretical upper bound of 100M. In practice, for T=25K and n=108, we observe that the algorithm gathers about 7M facts.) *) module T : sig (* [register fact] registers the fact [fact]. It returns [true] if this fact is new, i.e., no fact concerning the same triple of [position], [a], and [z] was previously known. *) val register: fact -> bool (* [query current z f] enumerates all known facts whose current state is [current] and whose lookahead assumption is compatible with [z]. The symbol [z] must a real terminal symbol, i.e., cannot be [any]. *) val query: Lr1.node -> Terminal.t -> (fact -> unit) -> unit (* [verbose()] outputs debugging & performance information. *) val verbose: unit -> unit end = struct (* We need to query the set of facts in two ways. In [register], we must test whether a proposed triple of [position], [a], [z] already appears in the set. In [query], we must find all facts that match a pair [current, z], where [current] is a state. (Note that [position] determines [current], but the converse is not true: a position contains more information besides the current state.) To address these needs, we use a two-level table. The first level is a matrix indexed by [current] and [z]. At the second level, we find sets of facts, where two facts are considered equal if they have the same triple of [position], [a], and [z]. In fact, we know at this level that all facts have the same [z] component, so only [position] and [a] are compared. Because our facts satisfy invariant 2, [z] is [any] if and only if the state [current fact] is solid. This means that we are wasting quite a lot of space in the matrix (for a solid state, the whole line is empty, except for the [any] column). *) (* The level-2 sets. *) module M = MySet.Make(struct type t = fact let compare fact1 fact2 = assert (fact1.lookahead = fact2.lookahead); let c = Trie.compare fact1.position fact2.position in if c <> 0 then c else let z = fact1.lookahead in let a1 = W.first fact1.word z and a2 = W.first fact2.word z in (* note: [a1] and [a2] can be [any] here *) Terminal.compare a1 a2 end) (* The level-1 matrix. *) let table = Array.make (Lr1.n * Terminal.n) M.empty let index current z = Terminal.n * (Lr1.number current) + Terminal.t2i z let count = ref 0 let register fact = let current = current fact in let z = fact.lookahead in let i = index current z in let m = table.(i) in (* We crucially rely on the fact that [M.add] guarantees not to change the set if an ``equal'' fact already exists. Thus, a later, longer path is ignored in favor of an earlier, shorter path. *) let m' = M.add fact m in m != m' && begin incr count; table.(i) <- m'; true end let query current z f = assert (not (Terminal.equal z any)); (* If the state [current] is solid then the facts that concern it are stored in the column [any], and all of them are compatible with [z]. Otherwise, they are stored in all columns except [any], and only those stored in the column [z] are compatible with [z]. *) let i = index current (if is_solid current then any else z) in let m = table.(i) in M.iter f m let verbose () = Printf.eprintf "T stores %d facts.\n%!" !count end (* ------------------------------------------------------------------------ *) (* The module [E] is in charge of recording the non-terminal edges that we have discovered, or more precisely, the conditions under which these edges can be taken. It maintains a set of quadruples [s, nt, w, z], where such a quadruple means that in the state [s], the outgoing edge labeled [nt] can be taken by consuming the word [w], under the assumption that the next symbol is [z]. Again, the terminal symbol [a], given by [W.first w z], plays a role. For each quadruple [s, nt, a, z], we store at most one quadruple [s, nt, w, z]. Thus, internally, we maintain a mapping of [s, nt, a, z] to [w]. For greater simplicity, we do not allow [z] to be [any] in [register] or [query]. Allowing it would complicate things significantly, it seems. *) module E : sig (* [register s nt w z] records that, in state [s], the outgoing edge labeled [nt] can be taken by consuming the word [w], if the next symbol is [z]. It returns [true] if this information is new, i.e., if the underlying quadruple [s, nt, a, z] is new. The symbol [z] cannot be [any]. *) val register: Lr1.node -> Nonterminal.t -> W.word -> Terminal.t -> bool (* [query s nt a z] enumerates all words [w] such that, in state [s], the outgoing edge labeled [nt] can be taken by consuming the word [w], under the assumption that the next symbol is [z], and the first symbol of the word [w.z] is [a]. The symbol [a] can be [any]. The symbol [z] cannot be [any]. *) val query: Lr1.node -> Nonterminal.t -> Terminal.t -> Terminal.t -> (W.word -> unit) -> unit (* [verbose()] outputs debugging & performance information. *) val verbose: unit -> unit end = struct (* At a high level, we must implement a mapping of [s, nt, a, z] to [w]. In practice, we can implement this specification using any combination of arrays, hash tables, balanced binary trees, and perfect hashing (i.e., packing several of [s], [nt], [a], [z] in one word.) Here, we choose to use an array, indexed by [s], of hash tables, indexed by a key that packs [nt], [a], and [z] in one word. According to a quick experiment, the final population of the hash table [table.(index s)] seems to be roughly [Terminal.n * Trie.size s]. We note that using an initial capacity of 0 and relying on the hash table's resizing mechanism has a significant cost, which is why we try to guess a good initial capacity. *) module H = Hashtbl let table = Array.init Lr1.n (fun i -> let size = Trie.size i in H.create (if size = 1 then 0 else Terminal.n * size) ) let index s = Lr1.number s let pack nt a z : int = (* We rely on the fact that we have at most 256 terminal symbols. *) (Nonterminal.n2i nt lsl 16) lor (Terminal.t2i a lsl 8) lor (Terminal.t2i z) let count = ref 0 let register s nt w z = assert (Terminal.real z); let i = index s in let m = table.(i) in let a = W.first w z in (* Note that looking at [a] in state [s] cannot cause an error. *) assert (not (causes_an_error s a)); let key = pack nt a z in if H.mem m key then false else begin incr count; H.add m key w; true end let rec query s nt a z f = assert (Terminal.real z); if Terminal.equal a any then begin (* If [a] is [any], we query the table for every real symbol [a]. We can limit ourselves to symbols that do not cause an error in state [s]. Those that do certainly do not have an entry; see the assertion in [register] above. *) foreach_terminal_not_causing_an_error s (fun a -> query s nt a z f ) end else begin let i = index s in let m = table.(i) in let key = pack nt a z in match H.find m key with | w -> f w | exception Not_found -> () end let verbose () = Printf.eprintf "E stores %d facts.\n%!" !count end (* ------------------------------------------------------------------------ *) (* [new_edge s nt w z] is invoked when we discover that in the state [s], the outgoing edge labeled [nt] can be taken by consuming the word [w], under the assumption that the next symbol is [z]. We check whether this quadruple already exists in the set [E]. If not, then we add it, and we compute its consequences, in the form of new facts, which we insert into the priority queue for later examination. *) let new_edge s nt w z = assert (Terminal.real z); if E.register s nt w z then let sym = Symbol.N nt in (* Query [T] for existing facts which could be extended by following this newly discovered edge. They must be facts whose current state is [s] and whose lookahead assumption is compatible with [a]. For each such fact, ... *) T.query s (W.first w z) (fun fact -> assert (compatible fact.lookahead (W.first w z)); (* ... try to take one step in the trie along an edge labeled [nt]. *) match Trie.step sym fact.position with | position -> (* This takes up to a new state whose incoming symbol is [nt]. Hence, this state is not solid. In order to satisfy invariant 2, we must create fact whose lookahead assumption is not [any]. That's fine, since our lookahead assumption is [z]. In order to satisfy invariant 1, we must check that [z] does not cause an error in this state. *) assert (not (is_solid (Trie.current position))); if not (causes_an_error (Trie.current position) z) then let word = W.append fact.word w in add { position; word; lookahead = z } | exception Not_found -> (* Could not take a step in the trie. This means this branch leads nowhere of interest, and was pruned when the trie was constructed. *) () ) (* ------------------------------------------------------------------------ *) (* [new_fact fact] is invoked when we discover a new fact (i.e., one that was not previously known). It studies the consequences of this fact. These consequences are of two kinds: - As in Dijkstra's algorithm, the new fact can be viewed as a newly discovered vertex. We study its (currently known) outgoing edges, and enqueue new facts in the priority queue. - Sometimes, a fact can also be viewed as a newly discovered edge. This is the case when the word that took us from [fact.source] to [fact.current] represents a production of the grammar and [fact.current] is willing to reduce this production. We record the existence of this edge, and re-inspect any previously discovered vertices which are interested in this outgoing edge. *) let new_fact fact = let current = current fact in (* 1. View [fact] as a vertex. Examine the transitions out of [current]. For every transition labeled by a symbol [sym] and into a state [target], ... *) Lr1.transitions current |> SymbolMap.iter (fun sym target -> (* ... try to follow this transition in the trie [fact.position], down to a child which we call [position]. *) match Trie.step sym fact.position, sym with | exception Not_found -> (* Could not take a step in the trie. This means this transition leads nowhere of interest. *) () | position, Symbol.T t -> (* 1a. The transition exists in the trie, and [sym] is in fact a terminal symbol [t]. We note that [t] cannot be the [error] token, because the trie does not have any edges labeled [error]. *) assert (Lr1.Node.compare (Trie.current position) target = 0); assert (is_solid target); assert (non_error t); (* If the lookahead assumption [fact.lookahead] is compatible with [t], then we derive a new fact, where one more edge has been taken, and enqueue this new fact for later examination. *) (* The state [target] is solid, i.e., its incoming symbol is terminal. This state is always entered without consideration for the next lookahead symbol. Thus, we can use [any] as the lookahead assumption in the new fact that we produce. If we did not have [any], we would have to produce one fact for every possible lookahead symbol. *) if compatible fact.lookahead t then let word = W.append fact.word (W.singleton t) in add { position; word; lookahead = any } | position, Symbol.N nt -> (* 1b. The transition exists in the trie, and [sym] is in fact a nonterminal symbol [nt]. *) assert (Lr1.Node.compare (Trie.current position) target = 0); assert (not (is_solid target)); (* We need to know how this nonterminal edge can be taken. We query [E] for a word [w] that allows us to take this edge. In general, the answer depends on the terminal symbol [z] that comes *after* this word: we try all such symbols. We must make sure that the first symbol of the word [w.z] satisfies the lookahead assumption [fact.lookahead]; this is ensured by passing this information to [E.query]. *) (* It could be the case that, due to a default reduction, the answer to our query does not depend on [z], and we are wasting work. However, allowing [z] to be [any] in [E.query], and taking advantage of this to increase performance, seems difficult. *) foreach_terminal_not_causing_an_error target (fun z -> E.query current nt fact.lookahead z (fun w -> assert (compatible fact.lookahead (W.first w z)); let word = W.append fact.word w in add { position; word; lookahead = z } ) ) ); (* 2. View [fact] as a possible edge. This is possible if the path from [fact.source] to the [current] state represents a production [prod] and [current] is willing to reduce this production. Then, reducing [prod] takes us all the way back to [fact.source]. Thus, this production gives rise to an edge labeled [nt] -- the left-hand side of [prod] -- out of [fact.source]. *) let z = fact.lookahead in if not (Terminal.equal z any) then begin (* 2a. The lookahead assumption [z] is a real terminal symbol. We check whether [current] is willing to reduce some production [prod] on [z], and whether the sub-trie [fact.position] accepts [prod], which means that this reduction takes us back to the root of the trie. If so, we have discovered a new edge. *) match has_reduction current z with | Some prod when Trie.accepts prod fact.position -> new_edge (source fact) (Production.nt prod) fact.word z | _ -> () end else begin (* 2b. The lookahead assumption is [any]. We must consider every pair [prod, z] such that the [current] state can reduce [prod] on [z] and [fact.position] accepts [prod]. *) match Invariant.has_default_reduction current with | Some (prod, _) -> if Trie.accepts prod fact.position then (* [new_edge] does not accept [any] as its 4th parameter, so we must iterate over all terminal symbols. *) foreach_terminal (fun z -> new_edge (source fact) (Production.nt prod) fact.word z ) | None -> TerminalMap.iter (fun z prods -> if non_error z then let prod = Misc.single prods in if Trie.accepts prod fact.position then new_edge (source fact) (Production.nt prod) fact.word z ) (Lr1.reductions current) end (* ------------------------------------------------------------------------ *) (* The main loop of the algorithm. *) let level, extracted, considered = ref 0, ref 0, ref 0 let done_with_level () = if X.verbose then begin Printf.eprintf "Done with level %d.\n" !level; W.verbose(); T.verbose(); E.verbose(); Printf.eprintf "Q stores %d facts.\n" (Q.cardinal q); Printf.eprintf "%d facts extracted out of Q, of which %d considered.\n%!" !extracted !considered end let () = Q.repeat q (fun fact -> incr extracted; if T.register fact then begin if W.length fact.word > !level then begin done_with_level(); level := W.length fact.word; end; incr considered; new_fact fact end ); done_with_level(); Time.tick "Running LRijkstra" (* ------------------------------------------------------------------------ *) (* The following code validates the fact that an error can be triggered in state [s'] by beginning in the initial state [s] and reading the sequence of terminal symbols [w]. We use this for debugging purposes. *) let fail msg = Printf.eprintf "coverage: internal error: %s.\n%!" msg; false open ReferenceInterpreter let validate s s' w : bool = match ReferenceInterpreter.check_error_path (Lr1.nt_of_entry s) (W.elements w) with | OInputReadPastEnd -> fail "input was read past its end" | OInputNotFullyConsumed -> fail "input was not fully consumed" | OUnexpectedAccept -> fail "input was unexpectedly accepted" | OK state -> Lr1.Node.compare state s' = 0 || fail ( Printf.sprintf "error occurred in state %d instead of %d" (Lr1.number state) (Lr1.number s') ) (* ------------------------------------------------------------------------ *) (* We now wish to determine, given a state [s'] and a terminal symbol [z], a minimal path that takes us from some entry state to state [s'] with [z] as the next (unconsumed) symbol. *) (* This can be formulated as a search for a shortest path in a graph. The graph is not just the automaton, though. It is a (much) larger graph whose vertices are pairs [s, z] and whose edges are obtained by querying the module [E] above. *) let forward () = let module A = Astar.Make(struct (* A vertex is a pair [s, z]. [z] cannot be the [error] token. *) type node = Lr1.node * Terminal.t let equal (s'1, z1) (s'2, z2) = Lr1.Node.compare s'1 s'2 = 0 && Terminal.compare z1 z2 = 0 let hash (s, z) = Hashtbl.hash (Lr1.number s, z) (* An edge is labeled with a word. *) type label = W.word (* Forward search from every [s, z], where [s] is an initial state. *) let sources f = foreach_terminal (fun z -> ProductionMap.iter (fun _ s -> f (s, z) ) Lr1.entry ) let successors (s, z) edge = assert (Terminal.real z); SymbolMap.iter (fun sym s' -> match sym with | Symbol.T t -> if Terminal.equal z t then let w = W.singleton t in foreach_terminal (fun z -> edge w 1 (s', z) ) | Symbol.N nt -> foreach_terminal (fun z' -> E.query s nt z z' (fun w -> edge w (W.length w) (s', z') ) ) ) (Lr1.transitions s) let estimate _ = 0 end) in (* Search forward. *) Printf.eprintf "Forward search:\n%!"; let seen = ref Lr1.NodeSet.empty in let _, _ = A.search (fun ((s', z), path) -> if causes_an_error s' z && not (Lr1.NodeSet.mem s' !seen) then begin seen := Lr1.NodeSet.add s' !seen; (* An error can be triggered in state [s'] by beginning in the initial state [s] and reading the sequence of terminal symbols [w]. *) let (s, _), ws = A.reverse path in let w = List.fold_right W.append ws (W.singleton z) in Printf.eprintf "An error can be reached from state %d to state %d:\n%!" (Lr1.number s) (Lr1.number s'); Printf.eprintf "%s\n%!" (W.print w); assert (validate s s' w) end ) in Printf.eprintf "Reachable (forward): %d states\n%!" (Lr1.NodeSet.cardinal !seen); !seen let () = let f = forward() in Time.tick "Forward search"; let stat = Gc.quick_stat() in Printf.eprintf "Maximum size reached by the major heap: %dM\n" (stat.Gc.top_heap_words * (Sys.word_size / 8) / 1024 / 1024); ignore f (* TODO: can we store fewer facts when we hit a default reduction? remove CompletedNatWitness?, revert Fix collect performance data, correlated with star size and alphabet size; draw a graph count the unreachable states and see if they are numerous in practice optionally report several ways of reaching an error in state s (with different lookahead tokens) (report all of them?) warn if --list-errors is set AND the grammar uses [error] control verbose output measure the cost of assertions remove $syntaxerror? how do we maintain the list of error messages when the grammar evolves? implement a naive semi-algorithm that enumerates all input sentences, and evaluate how well (or how badly) it scales *) end